我们都知道由于zh安全考虑，所有的地图无论百度还是高德地图都存在一定偏差，但有时候我们需要准确的定位就需要对经纬度进行纠偏，下面是我们做项目当中用到的纠偏算法，适用于高德地图，其它的未验证

高德地图纠偏算法

public class GspModified {
	    final static double pi = 3.14159265358979324;
	    final static double a = 6378245.0;
	    final static double ee = 0.00669342162296594323;
	  
	    public static void transform(double wgLat, double wgLon, double[] latlng) {
	        if (outOfChina(wgLat, wgLon)) {
	            latlng[0] = wgLat;
	            latlng[1] = wgLon;
	            return;
	        }
	        double dLat = transformLat(wgLon - 105.0, wgLat - 35.0);
	        double dLon = transformLon(wgLon - 105.0, wgLat - 35.0);
	        double radLat = wgLat / 180.0 * pi;
	        double magic = Math.sin(radLat);
	        magic = 1 - ee * magic * magic;
	        double sqrtMagic = Math.sqrt(magic);
	        dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
	        dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);
	        latlng[0] = wgLat + dLat;
	        latlng[1] = wgLon + dLon;
	    }
	  
	    private static boolean outOfChina(double lat, double lon) {
	        if (lon < 72.004 || lon > 137.8347)
	            return true;
	        if (lat < 0.8293 || lat > 55.8271)
	            return true;
	        return false;
	    }
	  
	    private static double transformLat(double x, double y) {
	        double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.sqrt(Math.abs(x));
	        ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;
	        ret += (20.0 * Math.sin(y * pi) + 40.0 * Math.sin(y / 3.0 * pi)) * 2.0 / 3.0;
	        ret += (160.0 * Math.sin(y / 12.0 * pi) + 320 * Math.sin(y * pi / 30.0)) * 2.0 / 3.0;
	        return ret;
	    }
	  
	    private static double transformLon(double x, double y) {
	        double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.sqrt(Math.abs(x));
	        ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;
	        ret += (20.0 * Math.sin(x * pi) + 40.0 * Math.sin(x / 3.0 * pi)) * 2.0 / 3.0;
	        ret += (150.0 * Math.sin(x / 12.0 * pi) + 300.0 * Math.sin(x / 30.0 * pi)) * 2.0 / 3.0;
	        return ret;
	    }
	
	 


}