Backspace String Compare

backspace-string-compare.py

class Solution(object):
    def backspaceCompare(self, S, T):
        """
        :type S: str
        :type T: str
        :rtype: bool
        """
        
        def deleteBackspace(word):
            temporal = [] 
            for w in word:
                if w != '#':
                    temporal.append(w)
                elif temporal:
                    temporal.pop()
            return ''.join(temporal)
        
        return deleteBackspace(S) == deleteBackspace(T)

I like the simplicity of the deleteBackspace method. Well done.

It is just a matter of look but I would replace lines 18 to 24 to be something like:

return deleteBackspace(S) == deleteBackspace(T)

def deleteBackspace(word):
temporal = []
for w in word:
if w != '#':
temporal.append(w)
elif temporal:
temporal.pop()
return ''.join(temporal)

    return deleteBackspace(S) == deleteBackspace(T)