0.date_number.py

_

date.py

#---------------------------------
# Converting Strings into Datetimes 
#---------------------------------
from datetime import datetime
text = '2012-09-20'
y = datetime.strptime(text, '%Y-%m-%d')
# for more, check http://strftime.org/

#---------------------------------
# Converting Datetimes into String
#---------------------------------
import datetime
from datetime.datetime import strftime as ft
z = datetime.datetime(2012, 9, 8, 7, 4, 3, 177393)
ft(z, '%Y-%m-%D %H:%M:%S') #=> '2012-09-08 07:04:03'

'{d.year}/{d.month}/{d.day} {d.hour}:{d.minute}:{d.second}'.format(d=z)
# => '2012-9-8 7:4:3'

datetime.isotime() #=> '2012-09-23T07:04:03'
ft(z, '%c') #=> 'Mon Sep 8 07:06:05 2012'
ft(z, '%x') #=> '2012-09-08'
ft(z, '%X') #=> '07:04:03'
# for more, check http://strftime.org/

#---------------------------------
# DateTime Algebra
#---------------------------------
# http://chimera.labs.oreilly.com/books/1230000000393/ch03.html#_solution_52
from datetime import timedelta
a = timedelta(days=2, hours=6)
b = timedelta(hours=4.5)
c = a + b
c.days #=> 2
c.seconds #=> 37800
c.seconds / 3600 #=> 10.5
c.total_seconds() / 3600 #=> 58.5

# If you need to represent specific dates and times, 
# create datetime instances and use the standard mathematical operations to manipulate them. 
from datetime import datetime
a = datetime(2012, 9, 23)
print(a + timedelta(days=10)) #=> 2012-10-03 00:00:00
b = datetime(2012, 12, 21)
d = b - a
d.days #=> 89
now = datetime.today()
print(now + timedelta(minutes=10)) #=> 2012-12-21 15:04:43.094063