Created
November 16, 2012 10:24
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Sum of LCP's of String with all its suffixes - The Z-Algorithm (linear time)
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| package strings; | |
| import java.util.Scanner; | |
| public class StringSimilarity { | |
| public static void solution1(){ | |
| Scanner sc = new Scanner(System.in); | |
| int num = sc.nextInt(); | |
| String input = null; | |
| char[] in = null; | |
| int len = 0; | |
| int pos=0; | |
| int overlap=0; | |
| for(int i=0; i<num; i++){ | |
| overlap=0; | |
| input = sc.next(); | |
| len = input.length(); | |
| in = input.toCharArray(); | |
| int[] z = new int[len]; /** This array will have LCP values **/ | |
| /** The Z-Algorithm: | |
| * Linear LCP calculation based on previous calculated lcp's **/ | |
| int L=0, R=0; | |
| int sum=0; | |
| for(int j=1; j<len; j++){ | |
| if(j>R){ | |
| L=R=j; | |
| while(R<len && in[R-L]==in[R]) | |
| R++; | |
| z[j]=R-L; | |
| R--; | |
| } | |
| else{ | |
| int k=j-L; | |
| if(z[k]<R-j+1) | |
| z[j]=z[k]; | |
| else{ | |
| L=j; | |
| while(R<len && in[R-L]==in[R]) | |
| R++; | |
| z[j]=R-L; | |
| R--; | |
| } | |
| } | |
| sum=sum+z[j]; | |
| } | |
| /*for(int ii:z) | |
| System.out.println(ii); | |
| */ | |
| System.out.println(sum+len); | |
| } | |
| } | |
| public static void main(String[] args){ | |
| StringSimilarity.solution1(); | |
| } | |
| } | |
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