Created
December 20, 2012 23:19
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Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
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| /** | |
| * Definition for binary tree | |
| * public class TreeNode { | |
| * int val; | |
| * TreeNode left; | |
| * TreeNode right; | |
| * TreeNode(int x) { val = x; } | |
| * } | |
| */ | |
| public class Solution { | |
| public boolean isValidBST(TreeNode root) { | |
| // Start typing your Java solution below | |
| // DO NOT write main() function | |
| return helper(root, Integer.MAX_VALUE, Integer.MIN_VALUE); | |
| } | |
| public boolean helper(TreeNode root, int max, int min){ | |
| if(root == null) | |
| return true; | |
| if(root.val < max && root.val > min && helper(root.left, root.val, min) && | |
| helper(root.right, max, root.val)) | |
| return true; | |
| return false; | |
| } | |
| } |
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