Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100".

AddBinary.java

public class Solution {
    public String addBinary(String a, String b) {
        // Start typing your Java solution below
        // DO NOT write main() function
        int la = a.length();
        int lb = b.length();
        
        int max = Math.max(la, lb);
        
        StringBuilder sum = new StringBuilder("");
        int carry = 0;
        
        for(int i = 0; i < max; i++){
            int m = getBit(a, la - i - 1);
            int n = getBit(b, lb - i - 1);
            int add = m + n + carry;
            sum.append(add % 2);
            carry = add / 2;
        }
        
        if(carry == 1)
            sum.append("1");
        
        return sum.reverse().toString();
        
    }
    
    public int getBit(String s, int index){
        if(index < 0 || index >= s.length())
            return 0;
        
        if(s.charAt(index) == '0')
            return 0;
        else
            return 1;
        
    }
}

In case anyone else meanders onto this, this can be done in what I think is an easier way by using built-in methods to the Integer class:

public class Solution{
public static String addBinary(String a, String b) {
int sum = Integer.parseInt(a,2) + Integer.parseInt(b,2);
System.out.println(sum);
System.out.println();
return Integer.toBinaryString(sum);
}
}

Integer.parseInt() is typically used to get an int from a string, however, when given a second argument, that argument acts as a radix (or a base) for it to convert from. By telling it to parse String a with radix 2, it converts the binary number given in String form, to an int in base 10 form. It does this to both the numbers being added, then adds them as ints. The new "sum" int is then returned as a binary String by running the toBinaryString method of Integer with the argument of the base 10 number you want to convert to binary.