bgauduch

Multiple git identities on one machine

TL;DR

One machine, several git identities: typically personal vs work, GitHub vs GitLab, or two accounts on the same provider. This setup makes every repository pick the right name, email, and keys on its own, so no work commit ever goes out under your personal address (or the reverse). In a hurry: run the Appendix B script once per identity.

ggarcia24

//The global script scope
def ctx = context(scope: scriptScope())

//What things can be on the script scope
contributor(ctx) {
    method(name: 'pipeline', type: 'Object', params: [body: Closure])
    property(name: 'params', type: 'org.jenkinsci.plugins.workflow.cps.ParamsVariable')
    property(name: 'env', type: 'org.jenkinsci.plugins.workflow.cps.EnvActionImpl.Binder')
    property(name: 'currentBuild', type: 'org.jenkinsci.plugins.workflow.cps.RunWrapperBinder')
    property(name: 'scm', type: 'org.jenkinsci.plugins.workflow.multibranch.SCMVar')

stellingsimon

package example.postgres.audit;

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

import java.sql.CallableStatement;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.SQLException;
import java.sql.Savepoint;

thehesiod

import asyncio
from datetime import datetime, timezone
import os

def utc_now():
    # utcnow returns a naive datetime, so we have to set the timezone manually <sigh>
    return datetime.utcnow().replace(tzinfo=timezone.utc)
  
class Terminator:
  pass

angstwad

import collections

def dict_merge(dct, merge_dct):
    """ Recursive dict merge. Inspired by :meth:``dict.update()``, instead of
    updating only top-level keys, dict_merge recurses down into dicts nested
    to an arbitrary depth, updating keys. The ``merge_dct`` is merged into
    ``dct``.

    :param dct: dict onto which the merge is executed
    :param merge_dct: dct merged into dct

Zearin

NOTE: This is a question I found on StackOverflow which I’ve archived here, because the answer is so effing phenomenal.

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Q: How can I make a chain of function decorators in Python?

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If you are not into long explanations, see [Paolo Bergantino’s answer][2].