Created
February 24, 2013 00:16
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Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
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/** | |
* Definition for binary tree | |
* struct TreeNode { | |
* int val; | |
* TreeNode *left; | |
* TreeNode *right; | |
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
public: | |
bool isValidBST(TreeNode *root) { | |
// Start typing your C/C++ solution below | |
// DO NOT write int main() function | |
return valid(root, numeric_limits<int>::min(), numeric_limits<int>::max()); | |
} | |
bool valid(TreeNode* root, int left, int right) { | |
if(root == NULL) { | |
return true; | |
} else if(root->val >= right or root->val <= left) { | |
return false; | |
} else { | |
return valid(root->left, left, root->val) and | |
valid(root->right, root->val, right); | |
} | |
} | |
}; |
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