Created
February 26, 2013 21:53
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Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below. For example, given the following triangle
[ [2], [3,4], [6,5,7], [4,1,8,3]
]
The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11).
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class Solution { | |
public: | |
int minimumTotal(vector<vector<int> > &triangle) { | |
// Start typing your C/C++ solution below | |
// DO NOT write int main() function | |
vector<int> second = triangle[triangle.size() - 1]; | |
for(int i = triangle.size() - 2; i >= 0; --i) { | |
vector<int> first = triangle[i]; | |
for(int j = 0; j < first.size(); ++j) { | |
first[j] += min(second[j], second[j + 1]); | |
} | |
second = first; | |
} | |
return second[0]; | |
} | |
}; |
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