Created
March 17, 2013 18:00
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Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.
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/** | |
* Definition for singly-linked list. | |
* struct ListNode { | |
* int val; | |
* ListNode *next; | |
* ListNode(int x) : val(x), next(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
public: | |
ListNode *deleteDuplicates(ListNode *head) { | |
// Start typing your C/C++ solution below | |
// DO NOT write int main() function | |
ListNode preHead(-1); | |
preHead.next = head; | |
ListNode* tmp = &preHead; | |
while(tmp->next != NULL) { | |
int val = tmp->next->val; | |
ListNode* post = tmp->next; | |
while(post->next != NULL and post->next->val == val) { | |
post = post->next; | |
} | |
if(tmp->next != post) { | |
tmp->next = post->next; | |
} else { | |
tmp = tmp->next; | |
} | |
} | |
return preHead.next; | |
} | |
}; |
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