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June 26, 2015 22:43
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Pack and unpack COBOL's COMP-3 numbers.
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#!/usr/bin/env python | |
# -*- coding: utf-8 -*- | |
""" | |
Pack and unpack COBOL's COMP-3 numbers. | |
Cobol stores most numbers as strings. There are times that they are stored in a | |
packed format ("Computational numbers"). Comp numbers are not stored like | |
traditional numbers (16-bit, 32-bit, 64-bit, etc), but in a bit length that is | |
four times the number of digits in the stored value plus four bits. For a | |
four-digit number (eg PIC 9(4) or PIC 9(2)V9(2)) the length of the stored value | |
will be 12 bits. | |
Each digit is stored in four bits. The number 4 becomes 0x4 (0100), 5 becomes | |
0x5 (0101), 6 becomes 0x6 (0110), etc. Once the full number is encoded (456) | |
an additional digit is placed on the end to denote positve or negative. 0xD is | |
negative, 0xC is positive, and while 0xF is unsigned. | |
Also note that decimals are not stored in numbers, computational or otherwise. | |
Decimals, and significant digits, are determined by the PICture clauses. The | |
number is loaded into the variable in COBOL and the PICture clause dictates | |
where the decimal should be. For example, given PIC 9(2)V9(2), the number is | |
stored on disk as a four digit integer, but when loaded it is represented in | |
memory as a two digit number with two additional digits of precision after a | |
decimal point. | |
For further information see the following pages: | |
http://3480-3590-data-conversion.com/article-cobol-comp.html | |
http://3480-3590-data-conversion.com/article-packed-fields.html | |
unpack_number() orignially from: | |
https://mail.python.org/pipermail/python-list/2000-April/050953.html | |
""" | |
from array import array | |
from struct import pack | |
def unpack_number(p): | |
""" Unpack a COMP-3 number. """ | |
a = array('B', p) | |
v = float(0) | |
# For all but last digit (half byte) | |
for i in a[:-1]: | |
v = (v * 100) + ( ( (i & 0xf0) >> 4) * 10) + (i & 0xf) | |
# Last digit | |
i = a[-1] | |
v = (v * 10) + ((i & 0xf0) >> 4) | |
# Negative/Positve check. | |
if (i & 0xf) == 0xd: | |
v = -v | |
# Decimal points are determined by a COBOL program's PICtrue clauses, not | |
# the data on disk. | |
return int(v) | |
def pack_number(n): | |
""" Pack a COMP-3 number. Format: PIC 9(9). """ | |
# Cobol numbers are stored without decimal info. Remove the decimal before | |
# calling pack_number() | |
n = int(n) | |
# Is the number negative? Remember for later. | |
negative = False | |
if n < 0: | |
negative = True | |
n *= -1 | |
# Treat the number as a string. Makes it easier to loop over. | |
n_str = str(n) | |
b = int(n_str[0]) | |
# For each digit, shift it onto the result. | |
for c in n_str[1:]: | |
b = (b << 4) | int(c) | |
# Make the number negative if needed. | |
if negative: | |
b = (b << 4) | 0xd | |
else: | |
b = (b << 4) | 0xf | |
# Pack the number as a long long and chop off the unused bits at the | |
# beginning. This will need to be changed for varying PICture clauses. | |
b_packed = pack('>q', b) | |
if len(b_packed) > 5: | |
b_packed = b_packed[-5:] | |
return b_packed | |
if __name__ == '__main__': | |
value = 123456 | |
packed = pack_number(value) | |
unpacked = unpack_number(packed) | |
hex_packed = ''.join( [ "%02X" % ord( chr(x) ) for x in packed ] ) | |
print('Value: {}\nPacked: 0x{}\nUnpacked: {}'.format(value, hex_packed, unpacked)) |
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It work's like charm and saved me a lot of time.
Thanks!