How to connect to An API using Java

Main.java

import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;

import java.net.HttpURLConnection;
import java.net.URL;
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {

        /*
        Maven dependency for JSON-simple:
            <dependency>
                <groupId>com.googlecode.json-simple</groupId>
                <artifactId>json-simple</artifactId>
                <version>1.1.1</version>
            </dependency>
         */

        try {
            //Public API:
            //https://www.metaweather.com/api/location/search/?query=<CITY>
            //https://www.metaweather.com/api/location/44418/

            URL url = new URL("https://www.metaweather.com/api/location/search/?query=London");

            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            conn.setRequestMethod("GET");
            conn.connect();

            //Check if connect is made
            int responseCode = conn.getResponseCode();

            // 200 OK
            if (responseCode != 200) {
                throw new RuntimeException("HttpResponseCode: " + responseCode);
            } else {

                StringBuilder informationString = new StringBuilder();
                Scanner scanner = new Scanner(url.openStream());

                while (scanner.hasNext()) {
                    informationString.append(scanner.nextLine());
                }
                //Close the scanner
                scanner.close();

                System.out.println(informationString);


                //JSON simple library Setup with Maven is used to convert strings to JSON
                JSONParser parse = new JSONParser();
                JSONArray dataObject = (JSONArray) parse.parse(String.valueOf(informationString));

                //Get the first JSON object in the JSON array
                System.out.println(dataObject.get(0));

                JSONObject countryData = (JSONObject) dataObject.get(0);

                System.out.println(countryData.get("woeid"));

            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

}

Thank you my friend!

Great Work, easy to understand! thx

I have been having a problem with this code, gives me "class org.json.simple.JSONObject cannot be cast to class org.json.simple.JSONArray" at line 45. Ive been stuck on this for some time, any idea why it doesnt work for me. Im running the code as it is

JSONParser parser = new JSONParser();
Object obj = parser.parse(String.valueOf(informationString));
JSONArray array = new JSONArray();
array.add(obj);

            System.out.println(array.get(0));

            JSONObject jsonObject = (JSONObject) array.get(0);
            System.out.println(jsonObject.get("woeid"));