Created
September 15, 2023 05:54
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Dijkstra
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| 108 | |
| 109 | |
| 110 | |
| 111 | |
| int N, M; | |
| int maze [MAX_N] [MAX_M]; | |
| int dis [MAX_N][MAX_M]; | |
| 112 | |
| int dijkstra(int sx, int sy, int tx, int ty) | |
| 1130 { | |
| 114 | |
| 115 | |
| priority_queue<T, vector<T›, greater<T›> pas | |
| 116 | |
| 117 | |
| memset (dis, INF8, sizeof (dis)) ; | |
| 118 | |
| 119 | |
| 120€ | |
| pq. emplace(maze [sx][sy], sx, sy) ; | |
| while (Ipq.empty () ) | |
| { | |
| 121 | |
| int d, ux, uy; | |
| 122 | |
| 123 | |
| 124 | |
| tie(d, ux, uy) = pq. top () , pq. pop () ; | |
| 125 | |
| if (dis [ux][uy] I= INF32) continue; | |
| 126 | |
| 127 | |
| 128 | |
| 129 E | |
| dis [ux][uy] = d; | |
| REP (i, 4) | |
| { | |
| 130 | |
| 131 | |
| int vx = ux + dx[i]; | |
| int vy = uy + dy[i]; | |
| 132 | |
| 133 | |
| 134 | |
| if (vx < 0 || N <= vX || vy < © || M <= vy || dis [vx][vy] != INF32) | |
| continue; | |
| 135 | |
| 136 | |
| 137 | |
| 138 | |
| pq. emplace (d + maze [vx][vy], vx, vy) ; | |
| }//REP | |
| }//while | |
| 139 | |
| 140 | |
| return dis [tx][ty]; | |
| 141 | |
| _ }//dijkstra |
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