Convert Integer to the Sum of Two No Zero Integers | Leetcode 1317

class Solution {
public:
    vector<int> getNoZeroIntegers(int n) {
        int a = 0;
        int b = 0;
        int power = 1;

        while(n){
            int digit = n%10;
            if(digit==0){
                a += 5 * power;
                b += 5 * power;
                n -= 10;
            }else if(digit==1 and n>=10){
                a += 5 * power;
                b += 6 * power;
                n -= 11;
            }else{
                int half = digit/2;
                a += half * power;
                b += (digit-half) * power;
            }
            power *= 10;
            n /= 10;
        }
        return {a,b};
    }
};
/*
// JAVA
class Solution {
    public int[] getNoZeroIntegers(int n) {
        int a = 0, b = 0;
        int power = 1;
        int m = n;

        while (m != 0) {
            int digit = m % 10;
            if (digit == 0) {
                a += 5 * power;
                b += 5 * power;
                m -= 10;
            } else if (digit == 1 && m >= 10) {
                a += 5 * power;
                b += 6 * power;
                m -= 11;
            } else {
                int half = digit / 2;
                a += half * power;
                b += (digit - half) * power;
            }
            power *= 10;
            m /= 10;
        }
        return new int[] {a, b};
    }
}

#Python
from typing import List

class Solution:
    def getNoZeroIntegers(self, n: int) -> List[int]:
        a = 0
        b = 0
        power = 1
        m = n

        while m != 0:
            digit = m % 10
            if digit == 0:
                a += 5 * power
                b += 5 * power
                m -= 10
            elif digit == 1 and m >= 10:
                a += 5 * power
                b += 6 * power
                m -= 11
            else:
                half = digit // 2
                a += half * power
                b += (digit - half) * power
            power *= 10
            m //= 10

        return [a, b]
*/