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Golang multipart/form-data File Upload
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package main | |
import ( | |
"net/http" | |
"os" | |
"bytes" | |
"path" | |
"path/filepath" | |
"mime/multipart" | |
"io" | |
) | |
func main() { | |
fileDir, _ := os.Getwd() | |
fileName := "upload-file.txt" | |
filePath := path.Join(fileDir, fileName) | |
file, _ := os.Open(filePath) | |
defer file.Close() | |
body := &bytes.Buffer{} | |
writer := multipart.NewWriter(body) | |
part, _ := writer.CreateFormFile("file", filepath.Base(file.Name())) | |
io.Copy(part, file) | |
writer.Close() | |
r, _ := http.NewRequest("POST", "http://example.com", body) | |
r.Header.Add("Content-Type", writer.FormDataContentType()) | |
client := &http.Client{} | |
client.Do(r) | |
} |
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No It doesn't.
If you want to achieve zero copy, you can use os.pipe instead of sendfile.
sendfile is fit to tcp package so, it is hard to use with http package.
See this code snippet and benchmarks of it.