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// i += 1 is a shorter way of writing i = i + 1 | |
for (i = 0; i < 5; i += 1) | |
{ // <-- the code block starts here | |
// Console.log expects a string, not a number | |
// so if we are going to log i we need to turn it into a string first | |
// using the toString function of the number: | |
let string_i = i.toString() | |
// Now we can log i: | |
console.log("Right now, i is " + string_i); | |
} // <-- the code block ends here | |
console.log("Next Example!") | |
let ages = [16, 87, 33, 12]; | |
// This time I'll use a different variable: j instead of i, just to show that you can. | |
// array.length gets the length (number of values) of an array | |
// so ages.length returns 4 because there are four numbers in ages, so this loop will run four times: | |
// which is perfect because there are only four ages to log: | |
for (j = 0; j < ages.length; j += 1) | |
{ | |
// Here we use j, which is the same j as the one above that keeps track of the index for the for loop | |
// so it will increment by 1 every time this loop is run. | |
// here we use j as the index for the age we want to retreive from the array ages: | |
// and because j increments each time the loop is run, the next age will be logged each time. | |
// like this: first age[0], then age[1], then age[2], then age[4]. | |
// First we need to turn the age, which is a number, into a string: | |
let string_age = ages[j].toString() | |
// And then we can log it: | |
console.log(string_age) | |
} |
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