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@chinchang
Last active September 7, 2023 02:39
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Function to convert XML to JSON
/**
* Changes XML to JSON
* Modified version from here: http://davidwalsh.name/convert-xml-json
* @param {string} xml XML DOM tree
*/
function xmlToJson(xml) {
// Create the return object
var obj = {};
if (xml.nodeType == 1) {
// element
// do attributes
if (xml.attributes.length > 0) {
obj["@attributes"] = {};
for (var j = 0; j < xml.attributes.length; j++) {
var attribute = xml.attributes.item(j);
obj["@attributes"][attribute.nodeName] = attribute.nodeValue;
}
}
} else if (xml.nodeType == 3) {
// text
obj = xml.nodeValue;
}
// do children
// If all text nodes inside, get concatenated text from them.
var textNodes = [].slice.call(xml.childNodes).filter(function(node) {
return node.nodeType === 3;
});
if (xml.hasChildNodes() && xml.childNodes.length === textNodes.length) {
obj = [].slice.call(xml.childNodes).reduce(function(text, node) {
return text + node.nodeValue;
}, "");
} else if (xml.hasChildNodes()) {
for (var i = 0; i < xml.childNodes.length; i++) {
var item = xml.childNodes.item(i);
var nodeName = item.nodeName;
if (typeof obj[nodeName] == "undefined") {
obj[nodeName] = xmlToJson(item);
} else {
if (typeof obj[nodeName].push == "undefined") {
var old = obj[nodeName];
obj[nodeName] = [];
obj[nodeName].push(old);
}
obj[nodeName].push(xmlToJson(item));
}
}
}
return obj;
}
/*
Usage:
1. If you have an XML file URL:
const response = await fetch('file_url');
const xmlString = await response.text();
var XmlNode = new DOMParser().parseFromString(xmlString, 'text/xml');
xmlToJson(XmlNode);
2. If you have an XML as string:
var XmlNode = new DOMParser().parseFromString(yourXmlString, 'text/xml');
xmlToJson(XmlNode);
3. If you have the XML as a DOM Node:
xmlToJson(YourXmlNode);
*/
@linhnt2803
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Love you <3 <3

@satriowibowo123
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Thank You very much @chinchang

@demircancelebi
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In case someone needs it, here is the ES6 version:

https://gist.github.com/demircancelebi/f0a9c7e1f48be4ea91ca7ad81134459d

@chhonmeily
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THANK YOU SO MUCH!!! GOD BLESS YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

@Teclogen
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Teclogen commented Sep 5, 2018

Your Logic Building is strong. Keep it Up

@iPzard
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iPzard commented Nov 29, 2018

You're a lifesaver!

@IlkerKadir
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Worked like a charm

@mombe090
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Wow Wow Wow Wow Wow guy u are a king @loveUGuy

@varadekd
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I am using the same code But when I am using the same code inside try and catch it is failing. The code was working fine but after updating node to 11.10.0, npm 6.8.0 and appium 1.11

@obisi7
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obisi7 commented Apr 24, 2019

Thanks for the code. I tried using the final version within a fetch call as shown below but I am getting this error: "Fetch TypeError: (0, _xmlTpJson.default) is undefined. I can't find any insight to the error or how to fix it. Please help and thanks.

` getNews() {
const link = "https://feeds.feedburner.com/morganstateu";

return fetch(link)
  .then(response => response.text())
  .then(response => {
    let resJson = xmlToJson(response);
    this.setState({
      data: resJson.rss.channel[0].item,
      isLoading: false,
      refreshing: false,
      error: response.error || null
    });
  })
  .catch(error => {
    this.setState({ error, isLoading: false });
    // Alert.alert("Error", "Sorry, something went wrong. Please try again");
    console.log('fetch', error)
  });

}`

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ghost commented Jun 19, 2019

I love you.
👍 😄

@chinchang
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Author

Updated with examples of how to use the function.

@chinchang
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@obisi7
You need to convert the response string into DOM before passing to xmlToJson:

let node = new DOMParser().parseFromString(response, 'text/xml')
let resJson = xmlToJson(node);

@themikesam
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how if contains cdata in a tags?

@oziresrds
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Thanks.

@olopsman
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Has anyone gotten it to work with creating an array?

@lhalvesf
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thank you!

@Qasim118
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I am facing an error " cannot convert undefined or null to object " in line 23

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