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Elastic transformation of an image in Python
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import numpy as np | |
from scipy.ndimage.interpolation import map_coordinates | |
from scipy.ndimage.filters import gaussian_filter | |
def elastic_transform(image, alpha, sigma, random_state=None): | |
"""Elastic deformation of images as described in [Simard2003]_. | |
.. [Simard2003] Simard, Steinkraus and Platt, "Best Practices for | |
Convolutional Neural Networks applied to Visual Document Analysis", in | |
Proc. of the International Conference on Document Analysis and | |
Recognition, 2003. | |
""" | |
assert len(image.shape)==2 | |
if random_state is None: | |
random_state = np.random.RandomState(None) | |
shape = image.shape | |
dx = gaussian_filter((random_state.rand(*shape) * 2 - 1), sigma, mode="constant", cval=0) * alpha | |
dy = gaussian_filter((random_state.rand(*shape) * 2 - 1), sigma, mode="constant", cval=0) * alpha | |
x, y = np.meshgrid(np.arange(shape[0]), np.arange(shape[1]), indexing='ij') | |
indices = np.reshape(x+dx, (-1, 1)), np.reshape(y+dy, (-1, 1)) | |
return map_coordinates(image, indices, order=1).reshape(shape) |
Sorry about my poor knowledge, but you are using gaussian filter for what exactly?
It is used to create the random deformations dx and dy. If you didn't have dx and dy, then the deformed mesh grid would be the same as the un-deformed mesh grid - so no deformation would happen
for those who have trouble with using this code
first, the image has to be square like: (x,x,3)
second, for showing the transformed image ex: transformed_image=elastic_transform(img,40,2) then using plt.imshow(transformed_image)
- The image does not have to be square
- The image has to be grayscale, i.e. the shape has to be (a,b) - this line of code makes sure of that
assert len(image.shape)==2
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for those who have trouble with using this code
first, the image has to be square like: (x,x,3)
second, for showing the transformed image ex: transformed_image=elastic_transform(img,40,2) then using plt.imshow(transformed_image)