Created
July 7, 2019 22:00
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Determines if a linked list is a palindrome. Both solutions work for a singly or doubly linked list.
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| func isPalindrome(_ list: DoublyLinkedList<String>) -> Bool { | |
| // Simple solution. Iterate over linked list and store as string. | |
| // Uses linear space and time. | |
| // Then compare string to a reversed string. | |
| // If equal, then we have a palindrome. | |
| var node = list.first | |
| var string = "" | |
| while node != nil { | |
| string += String(node!.element) | |
| node = node!.next | |
| } | |
| return string == String(string.reversed()) | |
| } | |
| func isPalindrome(_ list: SinglyLinkedList<String>) -> Bool { | |
| // Recursive solution. Uses constant space and linear time. | |
| // Checks first and last elements in linked list. | |
| // Removes elements from front and back until there | |
| // is one element, no elements, or an invalid palindrome is found. | |
| if list.isEmpty || list.first === list.last { | |
| return true | |
| } | |
| if list.first!.element == list.last!.element { | |
| _ = list.remove(node: list.first!) | |
| _ = list.remove(node: list.last!) | |
| return isPalindrome(list) | |
| } | |
| return false | |
| } |
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