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Compact C Hex Dump Function w/ASCII
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#include <stdio.h> | |
char* DumpHex2(const void* data, size_t size) { | |
const int symbolSize = 100; | |
char* buffer = calloc(10*size, sizeof(char)); | |
char* symbol = calloc(symbolSize, sizeof(char)); | |
char ascii[17]; | |
size_t i, j; | |
ascii[16] = '\0'; | |
for (i = 0; i < size; ++i) { | |
snprintf(symbol, symbolSize, "%02X ", ((unsigned char*)data)[i]); | |
strcat(buffer, symbol); | |
memset(symbol,0,strlen(symbol)); | |
if (((unsigned char*)data)[i] >= ' ' && ((unsigned char*)data)[i] <= '~') { | |
ascii[i % 16] = ((unsigned char*)data)[i]; | |
} else { | |
ascii[i % 16] = '.'; | |
} | |
if ((i+1) % 8 == 0 || i+1 == size) { | |
strcat(buffer, " "); | |
if ((i+1) % 16 == 0) { | |
snprintf(symbol, symbolSize, "| %s \n", ascii); | |
strcat(buffer, symbol); | |
memset(symbol,0,strlen(symbol)); | |
} else if (i+1 == size) { | |
ascii[(i+1) % 16] = '\0'; | |
if ((i+1) % 16 <= 8) { | |
strcat(buffer, " "); | |
} | |
for (j = (i+1) % 16; j < 16; ++j) { | |
strcat(buffer, " "); | |
} | |
snprintf(symbol, symbolSize, "| %s \n", ascii); | |
strcat(buffer, symbol); | |
memset(symbol,0,strlen(symbol)); | |
} | |
} | |
} | |
free(symbol); | |
return buffer; | |
} |
How did you compile it without main()?
you'll need a main() of some sort. I just added the function to an existing project and it just worked.
Thank you so much man👍👍👍
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Compiled first time with no corrections. Worked perfectly.
Don't forget to free those buffers after you're done folks!