Swift: split array by chunks of given size

splitBy.swift

let arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]

extension Array {
    func splitBy(subSize: Int) -> [[Element]] {
        return 0.stride(to: self.count, by: subSize).map { startIndex in
            let endIndex = startIndex.advancedBy(subSize, limit: self.count)
            return Array(self[startIndex ..< endIndex])
        }
    }
}

let chunks = arr.splitBy(5)

print(chunks) // [[1, 2, 3, 4, 5], [6, 7, 8, 9, 10], [11, 12]]

would be nice to have a Swift3 version :)

What I use for Swift 3.0:

    func chunk(_ chunkSize: Int) -> [[Element]] {
        return stride(from: 0, to: self.count, by: chunkSize).map({ (startIndex) -> [Element] in
            let endIndex = (startIndex.advanced(by: chunkSize) > self.count) ? self.count-startIndex : chunkSize
            return Array(self[startIndex..<startIndex.advanced(by: endIndex)])
        })
    }

Or even better: http://stackoverflow.com/a/38156873/406677

extension Array {
    func chunks(_ chunkSize: Int) -> [[Element]] {
        return stride(from: 0, to: self.count, by: chunkSize).map {
            Array(self[$0..<Swift.min($0 + chunkSize, self.count)])
        }
    }
}

@ALL thanks! everybody~

You're my hero guys!

How to get like this [["1","2","3","4"],["4","5","6","7"],["7","8","9"]]
Each set last item repeat of the start of second set.
Please help.

extension Array {
    func chunks(_ chunkSize: Int) -> [[Element]] {
        return stride(from: 0, to: self.count, by: chunkSize).map {
            Array(self[$0..<Swift.min($0 + chunkSize, self.count)])
        }
    }
}