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Swift: split array by chunks of given size
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let arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12] | |
extension Array { | |
func splitBy(subSize: Int) -> [[Element]] { | |
return 0.stride(to: self.count, by: subSize).map { startIndex in | |
let endIndex = startIndex.advancedBy(subSize, limit: self.count) | |
return Array(self[startIndex ..< endIndex]) | |
} | |
} | |
} | |
let chunks = arr.splitBy(5) | |
print(chunks) // [[1, 2, 3, 4, 5], [6, 7, 8, 9, 10], [11, 12]] |
extension Array {
func chunks(_ chunkSize: Int) -> [[Element]] {
return stride(from: 0, to: self.count, by: chunkSize).map {
Array(self[$0..<Swift.min($0 + chunkSize, self.count)])
}
}
}
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How to get like this [["1","2","3","4"],["4","5","6","7"],["7","8","9"]]
Each set last item repeat of the start of second set.
Please help.