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Consider a standard coordinate system C in three dimensions. Let a linear transformation R be any rotation or reflection | |
around or through the origin respectively. | |
Let R be applied to the orthonormal basis vectors that define the axis directions of C. Let R be applied to any points | |
in C, say P₀ and P₁. | |
R: C → C' | |
R: P₀, P₁ → P'₀, P'₁ | |
A new coordinate system C' results whose axis directions are the transformed axis directions of C under the |
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₀₁₂₃₄₅₆₇₈₉ ⁰¹²³⁴⁵⁶⁷⁸⁹ ⁺⁻⁼⁽⁾ ₐₑₕᵢⱼₖₗₘₙₒₚᵣₛₜᵤᵥₓᴬᴮᴰᴱᴳᴴᴵᴶᴷᴸᴹᴺᴼᴾᴿᵀᵁⱽᵂ | |
⋅±→∠⨯ √ ‥ | |
αβγδεζηθικλμνξοπρςστυφχψω | |
Α α, Β β, Γ γ, Δ δ, Ε ε, Ζ ζ, Η η, Θ θ, Ι ι, Κ κ, Λ λ, Μ μ, Ν ν, Ξ ξ, Ο ο, Π π, Ρ ρ, Σ σ/ς, Τ τ, Υ υ, Φ φ, Χ χ, Ψ ψ, Ω | |
ᵦ ᵧ ᵨ ᵩ ᵪ ᵅ ᵝ ᵞ ᵟ ᵋ ᶿ ᶥ ᶲ ᵠ ᵡ |
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Find the values of the parameter t (in the range 0..1 inclusive) at the intersection points of a quadratic Bezier curve | |
and a plane in three dimensions. | |
Let P₀, P₁, and P₂ be the control points of a quadratic Bezier curve B such that | |
B{t} = (1-t)²P₀ + 2(1-t)(t)P₁ + (t²)P₂ | |
Let A be a unit normal vector to the plane where Q is any position vector on the plane such that | |
A⋅Q = d |
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Produce a new function which is a horizontal reflection of the function f{x} in the vertical line x=k. | |
There are three steps: (1) horizontally translate the function in such a way that the reflection can be applied across the | |
Y-axis (i.e. all points on the translated function's curve should be the same distance from the Y-axis as they originally | |
were from the line x=k); (2) perform a reflection across the Y-axis; (3) reverse the translation made in step 1. | |
1. Consider the translation necessary to make the line x=k coincide with the Y-axis. Apply this translation to f{x} | |
producing f₁{x}. | |
f₁{x} = f{x+k} |
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/// Print the calculation which multiplies two 3x4 affine transformation | |
/// matrices. | |
/// | |
/// The matrices store their elements in a flat array in column order. | |
void main() { | |
StringBuffer buffer = new StringBuffer(); | |
String l = "a1"; | |
String r = "a2"; | |
for (int col in new Iterable.generate(4)) { | |
for (int row in new Iterable.generate(3)) { |
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/// Print the calculation which multiplies two 4x4 matrices. | |
/// | |
/// The matrices store their elements in a flat array in column order. | |
void main() { | |
StringBuffer buffer = new StringBuffer(); | |
String l = "m1"; | |
String r = "m2"; | |
for (int col in new Iterable.generate(4)) { | |
for (int row in new Iterable.generate(4)) { | |
buffer.writeAll([ |
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/// Print the calculation which multiplies two 3x3 matrices. | |
/// | |
/// The matrices store their elements in a flat array in column order. | |
void main() { | |
StringBuffer buffer = new StringBuffer(); | |
String l = "m1"; | |
String r = "m2"; | |
for (int col in new Iterable.generate(3)) { | |
for (int row in new Iterable.generate(3)) { | |
buffer.writeAll([ |
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