FizzBuzz Python Solution

FizzBuzz.py

def fizzbuzz(n):

    if n % 3 == 0 and n % 5 == 0:
        return 'FizzBuzz'
    elif n % 3 == 0:
        return 'Fizz'
    elif n % 5 == 0:
        return 'Buzz'
    else:
        return str(n)

print "\n".join(fizzbuzz(n) for n in xrange(1, 21))

mylist = ["FizzBuxx" if x%3==0 and x%5==0 else "Fizz" if x%3==0 else "Buzz" if x%5==0 else x for x in range(1,101)]

def fizzBuzz(n):
for i in range(1,n+1):
if (i%15 == 0):
print("FizzBuzz")
elif (i%3 == 0):
print("Fizz")
elif (i%5 == 0):
print("Buzz")
else:
print(i)

for the fizz buzz game how to get the output for total number of fizz, buzz and fizzbuzz

Try this. It's only 2 lines of code.
for i in range(1, 101):
----print("Fizz" * (i%3<1) + (i%5<1) * "Buzz" or i)

@RobertAtomic
I am new to Python, why should it be range(1, 101)?

101 will not be taken ex:

range(1,5)
print(range)

output:
>>(1,2,3,4)

so last number will not be taken in python

print("\n".join(["Fizz"*(i%3==0)+"Buzz"*(i%5==0) or str(i) for i in range(1,100)]))

Use this one , u get the real answer for the question.
print ("\n".join(["Fizz"(i%3==0)+"Buzz"(i%5==0) or str(i) for i in range(1,n+1)]))

I got answer and also passed all test cases, by using ur single line code thanks!

def fizzbuzz(x):
    is_fizz = x % 3 == 0
    is_buzz = x % 5 == 0

    if is_fizz and is_buzz:
        return 'FizzBuzz'

    if is_fizz:
        return 'Fizz'

    if is_buzz:
        return 'Buzz'

    return x


r = map(fizzbuzz, range(1, 100))

print(list(r))

def fizzBuzz(n):
for i in range(1,16):
if i % 3 == 0 and i % 5 == 0:
print('FizzBuzz')
elif i % 3 == 0:
print('fizz')
elif i % 5 == 0 :
print('buzz')
else:
print(i)
The easiest way I could do

def FizzBuzz(numbersAndWords):
    for i in range(100):
        outString = ""
        for number in numbersAndWords.keys():
            if i % number == 0:
                outString += numbersAndWords[number]
        if outString == "":
            outString = i
        print(str(outString))

inGoes = {
        3:"Fizz",
        5:"Buzz"
        }

FizzBuzz(inGoes)

My preferred solution

#!/bin/python3

import math
import os
import random
import re
import sys

Complete the 'fizzBuzz' function below.

The function accepts INTEGER n as parameter.

def fizzBuzz(n):

for x in list(range(1,n+1)):
output = ""
if(x % 3 == 0):
output += 'Fizz'
if(x % 5 == 0):
output += 'Buzz'
if(output == ""):
output += str(x)

print(output)
# Write your code here

if name == 'main':
n = int(input().strip())

fizzBuzz(n)

In an interval of (1,N+1) the fuction will print Fizz if i value is divisible by 3, Buzz if is divisible by 5, and FizzBuzz if divisible by both. Else if none is true, it prints i.

def fizzbuzz(n):
   for i in range(1,n+1):
   txt=''

   if(x%3==0):
     txt+='Fizz'

   if(x%5==0):
     txt+='Buzz'

   print(txt) if len(txt)>0 else print(i)

   return

if __name__ = '__main__':
   n = int(input().strip())
   fizzbuzz(n)

for n in range(1, 101):
    if not n % 3 and not n % 5:
        print('FizzBuzz')
    elif not n % 3:
        print('Fizz')
    elif not n % 5:
        print('Buzz')
    else:
        print(n)

In 480 bits (60 bytes) or 60 chars:

for i in range(100):print(i%3//2*'Fizz'+i%5//4*'Buzz'or i+1)

def fizzBuzz(n):
# Write your code here
for i in range(1, n + 1):
if i % 5 == 0 and i % 5 == 0:
print("FizzBuzz")
elif i % 3 == 0:
print("Fizz")
elif i % 5 == 0:
print("Buzz")
elif i % 3 != 0 or i % 5 != 0:
print(str(i))

Proof, code at work

def fizzBuzz():
stack = range(1, 100, 1)
for item in stack:
if item % 3 == 0 and item % 5 == 0:
item = "FizzBuzz"
elif item % 3 == 0:
item = "Fizz"
elif item % 5 == 0:
item = "Buzz"

    print(item)

fizzBuzz()