-
-
Save jdpaton/2210886 to your computer and use it in GitHub Desktop.
python -c "import random; x = [random.choice('23456789') for x in range(1)] + [ random.choice('abcdefghjkmnpqrstwxyz') for x in range(3)]; random.shuffle(x); print ''.join(x)" |
I still need to figure out how to only generate one number and randomise it's position....
python -c"".join(('abcdefghjkmnpqrstqxyz'*12)[ord(x)][0]+('23456789'*50)[ord(x)][0] for x in __import__('os').urandom(2))"
(Note the 'u' is gone too, forgot to mention that character can be dropped)
Jan, it's not easy to see how you are not generating the numeric zero / 1, are you starting the numeric index from > 1? I'm intrigued :)
chr 50 == 2 + [0..7](rand 8). I don't know that we need full readability on this, and the no-external modules perl solution seems fine as it fills all the criteria, even randomizing the digit. I need 1..4 to get 4 chars though. Jan - is that a buglet?
@jeff-hobbs: Yes, my latest entry should have 1..4 in it. And dropping the 'u' saves another character:
perl -e'@_=map substr(abcdefghjkmnpqrstwxyz,rand 21,1),1..4;splice@_,rand@_,1,chr 50+rand 8;print @_'
Finally, I would like to change @_ to @$ as a hidden reference to ActiveState (@$ is ActiveState similar to how *$ is Starbucks):
perl -e'@$=map substr(abcdefghjkmnpqrstwxyz,rand 21,1),1..4;splice@$,rand@$,1,chr 50+rand 8;print @$'
Easier to understand and 3 characters shorter: