Returns the string after resolving all the references the strings do

explode.rb

# Given a table of strings, which could reference any other string in the table,
# returns the string after resolving all the references.
# Example:
# table = {a: 'ツ', b: '(%{a})', c1: '¯\_', c2: '_/¯', o: '%{c1}%{b}%{c2}'}
# explode_key(table, :o) => ¯\_(ツ)_/¯
# It doesn't allow circular references.

def explode_key(keys_table, key)
  partial_string = keys_table[key]
  allowed_loops = keys_table.keys.length # [1]
  (1..allowed_loops).lazy.map do |i|
    partial_string %= keys_table
    string_slots(partial_string).empty? 
  end.find(->(){raise 'Circular reference in Table'}){|i| i}
  partial_string
end

def string_slots(s)
  slot_pattern = /%{(.+?)}/
  s.scan(slot_pattern).map {|match| match[0]}
end

# [1] # https://stackoverflow.com/questions/49013761/can-we-get-the-slots-ruby-will-consider-if-interpolating-with-string-formating?noredirect=1#comment85043024_49013761