John McCardle Solders & Hacks jmccardle

Convert Discussion To Video Content - Full Script

You are a video scriptwriter specializing in educational YouTube content. Your task is to expand a finalized video outline into a complete, ready-to-record script that maintains the strategic timing and rhetorical approach specified in the outline.

Input Requirements

You need:

A finalized video outline (from /video-outline or user-created)
The original conversation history (for context, examples, and specific details)
Any additional notes or revisions discussed after the outline was created

Convert Discussion To Video Content - Outline

You are a video content strategist specializing in educational YouTube content about technical topics. Your task is to convert a conversation into a structured video outline with precise timing and rhetorical strategy.

Input Context

You have access to:

The full conversation history leading up to this command
Any web research, articles, or passages discussed
Examples, data points, and theories developed during the discussion

	class BinaryNode:
	__slots__ = ("value", "left", "right")
	def __init__(self, value=None, left=None, right=None):
	self.value = value
	self.left = left
	self.right = right

	def __repr__(self):
	return f"<BinaryNode value={self.value}; {1 if self.left else 0 + 1 if self.right else 0} children>"

	# See this diagram: https://i.redd.it/41iyyfdaliab1.png
	from itertools import permutations
	for i, perm in enumerate(permutations([1,2,3,4,6,8,9])):
	a, b, c, d, e, f, g = perm
	if (a + d + g + f) +1 == (b + d + e + g) -1 == (c * e * f * g +1)**0.5:
	print(f"\n{i}. Solution: a = {a}, b = {b}, c = {c}, d = {d}, e = {e}, f = {f}, g = {g}, x = {(a+d+g+f)+1}")
	elif i % 10 == 0:
	print(f".", end='')

	# See diagram: https://i.imgur.com/UWDrqcH.png

	# We need 8 equations to solve the diagram, but I can only come up with 5.
	# For three more equations, we will assume a value for X, A, and D.
	# If sympy times out, we will cancel the attempt.

	# Values for X: 7 choose 4, 35 possible values.
	# Values for A: 7.
	# (Naive) Maximum loops: 7*35 = 245.
	# (actual) maximum loops: 4 * 35 = 140. A has to be in the circle for the solution for X we're using.

	# See diagram: https://i.imgur.com/UWDrqcH.png

	from itertools import permutations
	for i, perm in enumerate(permutations([1,2,3,4,5,6,7])):
	a, b, c, d, e, f, g = perm
	if (a + d + g + f) / 2 == (b + d + e + g) / 3 == (c + e + f + g) / 4:
	print(f"\n{i}. Solution: a = {a}, b = {b}, c = {c}, d = {d}, e = {e}, f = {f}, x = {(a+d+g+f)/2}")
	else:
	print(f"{i} ", end='')

	# (Major issues) - not enough equations to solve this SOE!
	# See diagram: https://i.imgur.com/UWDrqcH.png

	# We need 7 equations to solve the diagram, but I can only come up with 5.
	# For two more equations, we will assume a value for X and A.
	# If sympy times out, we will cancel the attempt.

	# Values for X: 7 choose 4, 35 possible values.
	# Values for A: 7.
	# (Naive) Maximum loops: 7*35 = 245.

	import pandas as pd
	def region(row):
	#print(row)
	state = row["state"]
	if state in ("FL", "GA"): return "South"
	elif state in ("CA", "WA"): return "West"
	elif state in ("MT", "MN"): return "Central"
	elif state in ("NY", "ME"): return "North"
	else: return "Unknown"