Shell - Get latest release from GitHub

get_latest_release.sh

get_latest_release() {
  curl --silent "https://api.github.com/repos/$1/releases/latest" | # Get latest release from GitHub api
    grep '"tag_name":' |                                            # Get tag line
    sed -E 's/.*"([^"]+)".*/\1/'                                    # Pluck JSON value
}

# Usage
# $ get_latest_release "creationix/nvm"
# v0.31.4

owner_repo='igniterealtime/Spark'; latest_version_url="$(curl -s https://api.github.com/repos/$owner_repo/releases/latest | grep "browser_download_url.*deb" | cut -d : -f 2,3 | tr -d ")"; echo $latest_version_url; basename $latest_version_url ; wget --content-disposition $latest_version_url

Thanks a lot! Although it's possible to just use curl instead of wget:
owner_repo='owner/name'; latest_version_url="$(curl -s https://api.github.com/repos/$owner_repo/releases/latest| grep "browser_download_url.*extension" | cut -d : -f 2,3 | tr -d \")"; echo $latest_version_url; basename $latest_version_url ; curl -X GET $latest_version_url -LO or -Lo name.extension

owner_repo='igniterealtime/Spark'; latest_version_url="$(curl -s https://api.github.com/repos/$owner_repo/releases/latest | grep "browser_download_url.*deb" | cut -d : -f 2,3 | tr -d ")"; echo $latest_version_url; basename $latest_version_url ; wget --content-disposition $latest_version_url

Thanks a lot! Although it's possible to just use curl instead of wget: owner_repo='owner/name'; latest_version_url="$(curl -s https://api.github.com/repos/$owner_repo/releases/latest| grep "browser_download_url.*extensions" | cut -d : -f 2,3 | tr -d \")"; echo $latest_version_url; basename $latest_version_url ; curl -X GET $latest_version_url -LO or -Lo name.extension

Awesome thanks for sharing. That is cool always wondered how to do that in curl but never bothered to look. Appreciate the share and explanation.

With the last update, the above breaks for me. I'm now using this:

latest_version_raw="$(curl -s https://api.github.com/repos/$owner_repo/releases | grep -m 1 "html_url" | rev | cut -    d/ -f1 | rev  )"
latest_version="${latest_version_raw%??}" # remove last 2 characters

Here's an example with wget & jq:

REPO="..."
VERSION=$(wget -q -O- https://api.github.com/repos/${REPO}/releases/latest | jq -r '.name')

Here's an example with wget & jq:

REPO="..."
VERSION=$(wget -q -O- https://api.github.com/repos/${REPO}/releases/latest | jq -r '.name')

that works great! but if prefer tag name instead of release name, use:

.tag_name

for how todo this on GitLab site, see my gist here:
https://gist.github.com/roelds/b2cd9cc2ba6c7887ddaf6bde2ef7ef50

One-liner using only curl + grep:
curl --silent "https://api.github.com/repos/${REPO}/releases/latest" | grep -Po "(?<=\"tag_name\": \").*(?=\")"

For the gh-cli inclined:

gh release list --exclude-pre-releases --json tagName,isLatest --jq '.[] | select(.isLatest) | .tagName'