Using d3-brush to zoom to the brushed region. Double-click or double-tap to zoom out. Another approach is to use Focus + Context.
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June 16, 2020 16:28
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Brush & Zoom II
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license: gpl-3.0 | |
height: 600 |
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<!DOCTYPE html> | |
<meta charset="utf-8"> | |
<svg width="960" height="600"></svg> | |
<script src="//d3js.org/d3.v4.min.js"></script> | |
<script> | |
var random = d3.randomNormal(0, 0.2), | |
sqrt3 = Math.sqrt(3), | |
points0 = d3.range(300).map(function() { return [random() + sqrt3, random() + 1, 0]; }), | |
points1 = d3.range(300).map(function() { return [random() - sqrt3, random() + 1, 1]; }), | |
points2 = d3.range(300).map(function() { return [random(), random() - 1, 2]; }), | |
points = d3.merge([points0, points1, points2]); | |
var svg = d3.select("svg"), | |
width = +svg.attr("width"), | |
height = +svg.attr("height"); | |
var k = height / width, | |
x0 = [-4.5, 4.5], | |
y0 = [-4.5 * k, 4.5 * k], | |
x = d3.scaleLinear().domain(x0).range([0, width]), | |
y = d3.scaleLinear().domain(y0).range([height, 0]), | |
z = d3.scaleOrdinal(d3.schemeCategory10); | |
var xAxis = d3.axisTop(x).ticks(12), | |
yAxis = d3.axisRight(y).ticks(12 * height / width); | |
var brush = d3.brush().on("end", brushended), | |
idleTimeout, | |
idleDelay = 350; | |
svg.selectAll("circle") | |
.data(points) | |
.enter().append("circle") | |
.attr("cx", function(d) { return x(d[0]); }) | |
.attr("cy", function(d) { return y(d[1]); }) | |
.attr("r", 2.5) | |
.attr("fill", function(d) { return z(d[2]); }); | |
svg.append("g") | |
.attr("class", "axis axis--x") | |
.attr("transform", "translate(0," + (height - 10) + ")") | |
.call(xAxis); | |
svg.append("g") | |
.attr("class", "axis axis--y") | |
.attr("transform", "translate(10,0)") | |
.call(yAxis); | |
svg.selectAll(".domain") | |
.style("display", "none"); | |
svg.append("g") | |
.attr("class", "brush") | |
.call(brush); | |
function brushended() { | |
var s = d3.event.selection; | |
if (!s) { | |
if (!idleTimeout) return idleTimeout = setTimeout(idled, idleDelay); | |
x.domain(x0); | |
y.domain(y0); | |
} else { | |
x.domain([s[0][0], s[1][0]].map(x.invert, x)); | |
y.domain([s[1][1], s[0][1]].map(y.invert, y)); | |
svg.select(".brush").call(brush.move, null); | |
} | |
zoom(); | |
} | |
function idled() { | |
idleTimeout = null; | |
} | |
function zoom() { | |
var t = svg.transition().duration(750); | |
svg.select(".axis--x").transition(t).call(xAxis); | |
svg.select(".axis--y").transition(t).call(yAxis); | |
svg.selectAll("circle").transition(t) | |
.attr("cx", function(d) { return x(d[0]); }) | |
.attr("cy", function(d) { return y(d[1]); }); | |
} | |
</script> |
Would it be possible to update the code of the graph for V5?
Akshay, the reason for the timeout is to capture double click events. Mouse-up on the graph triggers a brush end. The first time this happens, we set the timer to clear idleTimeout
, which tracks whether we've recently (at most idleDelay
ms ago) clicked. The second time we mouse-up, one of two things can happen: either the timer has expired, in which case idleTimeout
is null
again and so we return without changing things; or the timer hasn't expired, in which case idleTimeout
is not null
and we continue on to set x.domain
and y.domain
.
In other words the timer is there to make sure we've double clicked and not just single clicked.
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I am not sure if this is the right place to ask this question, but I don't understand the purpose of the following code.
I know how
setTimeout
behaves, but not sure how and why it's used like this, and how it fits in with the rest of the code.