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@mizar
Last active May 23, 2022 08:56
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πŸ‘‡

$$ \operatorname{I}_x(a,b)=\dots, d_{2n}=\dots $$

πŸ‘†

$$ \operatorname{I}_x(a,b)=\dots, d_{2n}=\dots $$

πŸ‘‡

$$ {\log}_x d_{2n} $$

πŸ‘†

$$ {\log}_x d_{2n} $$

πŸ‘‡

$$ \operatorname{I}_x(a,b)=\dots, d_{2n}=\dots $$

πŸ‘†

$$ \operatorname{I}\_x(a,b)=\dots, d\_{2n}=\dots $$

πŸ‘‡

$$ {\log}_x d_{2n} $$

πŸ‘†

$$ {\log}\_x d\_{2n} $$

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