Palyndrome dates generator (Javascript)

palyndrome.js

function palindrome(str) {
  // Step 1. Lowercase the string and use the RegExp to remove unwanted characters from it
  var re = /[\W_]/g; // or var re = /[^A-Za-z0-9]/g;
  
  var lowRegStr = str.toLowerCase().replace(re, '');
  // str.toLowerCase() = "A man, a plan, a canal. Panama".toLowerCase() = "a man, a plan, a canal. panama"
  // str.replace(/[\W_]/g, '') = "a man, a plan, a canal. panama".replace(/[\W_]/g, '') = "amanaplanacanalpanama"
  // var lowRegStr = "amanaplanacanalpanama";
     
  // Step 2. Use the same chaining methods with built-in functions from the previous article 'Three Ways to Reverse a String in JavaScript'
  var reverseStr = lowRegStr.split('').reverse().join(''); 
  // lowRegStr.split('') = "amanaplanacanalpanama".split('') = ["a", "m", "a", "n", "a", "p", "l", "a", "n", "a", "c", "a", "n", "a", "l", "p", "a", "n", "a", "m", "a"]
  // ["a", "m", "a", "n", "a", "p", "l", "a", "n", "a", "c", "a", "n", "a", "l", "p", "a", "n", "a", "m", "a"].reverse() = ["a", "m", "a", "n", "a", "p", "l", "a", "n", "a", "c", "a", "n", "a", "l", "p", "a", "n", "a", "m", "a"]
  // ["a", "m", "a", "n", "a", "p", "l", "a", "n", "a", "c", "a", "n", "a", "l", "p", "a", "n", "a", "m", "a"].join('') = "amanaplanacanalpanama"
  // So, "amanaplanacanalpanama".split('').reverse().join('') = "amanaplanacanalpanama";
  // And, var reverseStr = "amanaplanacanalpanama";
   
  // Step 3. Check if reverseStr is strictly equals to lowRegStr and return a Boolean
  return reverseStr === lowRegStr; // "amanaplanacanalpanama" === "amanaplanacanalpanama"? => true
}

// Returns an array of dates between the two dates
function getDates (startDate, endDate) {
  const dates = []
  let currentDate = startDate
  const addDays = function (days) {
    const date = new Date(this.valueOf())
    date.setDate(date.getDate() + days)
    return date
  }
  while (currentDate <= endDate) {
    dates.push(currentDate)
    currentDate = addDays.call(currentDate, 1)
  }
  return dates
}

function padTo2Digits(num) {
  return num.toString().padStart(2, '0');
}

function formatDate(date) {
  return [
    padTo2Digits(date.getDate()),
    padTo2Digits(date.getMonth() + 1),
    date.getFullYear(),
  ].join('/');
}

const dates = getDates(new Date(2022, 02, 22), new Date(3001, 03, 10))
dates.forEach(function (date) {
  if ( palindrome( formatDate(date) ) )
    console.log( formatDate(date) );
});