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@svdamani
Last active August 19, 2024 07:51
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Natural Cubic Spline Interpolation in C
/** Numerical Analysis 9th ed - Burden, Faires (Ch. 3 Natural Cubic Spline, Pg. 149) */
#include <stdio.h>
int main() {
/** Step 0 */
int n, i, j;
scanf("%d", &n);
n--;
float x[n + 1], a[n + 1], h[n], A[n], l[n + 1],
u[n + 1], z[n + 1], c[n + 1], b[n], d[n];
for (i = 0; i < n + 1; ++i) scanf("%f", &x[i]);
for (i = 0; i < n + 1; ++i) scanf("%f", &a[i]);
/** Step 1 */
for (i = 0; i <= n - 1; ++i) h[i] = x[i + 1] - x[i];
/** Step 2 */
for (i = 1; i <= n - 1; ++i)
A[i] = 3 * (a[i + 1] - a[i]) / h[i] - 3 * (a[i] - a[i - 1]) / h[i - 1];
/** Step 3 */
l[0] = 1;
u[0] = 0;
z[0] = 0;
/** Step 4 */
for (i = 1; i <= n - 1; ++i) {
l[i] = 2 * (x[i + 1] - x[i - 1]) - h[i - 1] * u[i - 1];
u[i] = h[i] / l[i];
z[i] = (A[i] - h[i - 1] * z[i - 1]) / l[i];
}
/** Step 5 */
l[n] = 1;
z[n] = 0;
c[n] = 0;
/** Step 6 */
for (j = n - 1; j >= 0; --j) {
c[j] = z[j] - u[j] * c[j + 1];
b[j] = (a[j + 1] - a[j]) / h[j] - h[j] * (c[j + 1] + 2 * c[j]) / 3;
d[j] = (c[j + 1] - c[j]) / (3 * h[j]);
}
/** Step 7 */
printf("%2s %8s %8s %8s %8s\n", "i", "ai", "bi", "ci", "di");
for (i = 0; i < n; ++i)
printf("%2d %8.2f %8.2f %8.2f %8.2f\n", i, a[i], b[i], c[i], d[i]);
return 0;
}
@Pin09091
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Hey so im making a hyper specific library for matlab, to use in a project, is it fine if i use this? and if i do then how should i credit you?

@Pin09091
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after testing it a bunch, if you want to use the values in a polynomial to find out querry points, a , b , c and d are in the reverse order,

i compared it to here : https://www.bragitoff.com/2018/02/cubic-spline-piecewise-interpolation-c-program/?unapproved=60552&moderation-hash=d514da745560ff352ee385453b9346e1#comment-60552

@svdamani
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svdamani commented Aug 19, 2024

Hey so im making a hyper specific library for matlab, to use in a project, is it fine if i use this? and if i do then how should i credit you?

@Pin09091 yes of course. Feel free to use it, mention link to the gist of my name. I'm glad this code is useful for you

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