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August 29, 2015 14:12
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This R script shows just how hard even trivial k-means clustering can be (with Lloyd's algorithm) by generating trivially clusterable data and then failing.
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# picking the corners of the hyper cube at random usually gives us a good selection | |
d = 0 | |
while (d == 0) { | |
centers = matrix(runif(10*10)>0.5, ncol=10) + 0 | |
# but occasionally we get a duplicate row that is easily detected | |
d = det(centers) | |
} | |
# start x out by selecting clusters | |
x = data.frame(n = ceiling(runif(10000,1e-10,10))) | |
for (i in 1:10) { | |
# then put in the coordinate of each column with a bit of noise | |
x = cbind(x, centers[x$n,i] + rnorm(dim(x)[1], 0, 1e-3)) | |
} | |
names(x) = c("n", paste("V", 1:10, sep="")) | |
# then cluster and plot. Ideally, all counts will be nearly equal. | |
fail = 0 | |
success = 0 | |
counts = rep(0,100) | |
for (i in 1:100) { | |
k = kmeans(x[,2:11], centers=10, nstart=1) | |
cnt = colSums(table(k$cluster, x$n) > 0) | |
counts[i] = max(cnt) | |
if (any(cnt > 1)) { | |
fail = fail + 1 | |
} else { | |
success = success + 1 | |
} | |
} | |
print(list(fail = fail, success = success)) | |
print(table(counts)) | |
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