Last active
February 25, 2018 14:13
-
-
Save webstory/ec885b3879014431d8180031cd8dc497 to your computer and use it in GitHub Desktop.
Backpressure - Controllable RxJS Producer
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
const rx = require('rx') | |
let s = new rx.Observable.from([1,2,3,4,5,6,7,8,9]) | |
let ss = s.controlled() | |
ss.subscribe((x) => { | |
console.log("Pull "+x) | |
setTimeout(() => process(1, x), 100) | |
}) | |
function process(i, x) { | |
if(i == 3) { | |
ss.request(1) | |
return | |
} | |
console.log('Process ${i} - ${x}') | |
setTimeout(() => process(i + 1, x), 100) | |
} | |
ss.request(1) |
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
const rx = require('rx') | |
let s = new rx.Subject() | |
let ss = s.controlled() | |
ss.subscribe((x) => { | |
console.log("Pull "+x) | |
setTimeout(() => process(1, x), 100) | |
}) | |
function process(i, x) { | |
if(i == 3) { | |
ss.request(1) | |
return | |
} | |
console.log(`Process ${i} - ${x}`) | |
setTimeout(() => process(i + 1, x), 100) | |
} | |
for(let i = 0; i < 100000; i++) { | |
s.onNext(i) | |
} | |
ss.request(1) |
The first subscriber will be blocked until call ss.request(1), therefore it must called into the last callback chain.
Why pausable() not work?
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
npm install rx
(Use rx package, not rxjs)