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Backpressure - Controllable RxJS Producer
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| const rx = require('rx') | |
| let s = new rx.Observable.from([1,2,3,4,5,6,7,8,9]) | |
| let ss = s.controlled() | |
| ss.subscribe((x) => { | |
| console.log("Pull "+x) | |
| setTimeout(() => process(1, x), 100) | |
| }) | |
| function process(i, x) { | |
| if(i == 3) { | |
| ss.request(1) | |
| return | |
| } | |
| console.log('Process ${i} - ${x}') | |
| setTimeout(() => process(i + 1, x), 100) | |
| } | |
| ss.request(1) |
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| const rx = require('rx') | |
| let s = new rx.Subject() | |
| let ss = s.controlled() | |
| ss.subscribe((x) => { | |
| console.log("Pull "+x) | |
| setTimeout(() => process(1, x), 100) | |
| }) | |
| function process(i, x) { | |
| if(i == 3) { | |
| ss.request(1) | |
| return | |
| } | |
| console.log(`Process ${i} - ${x}`) | |
| setTimeout(() => process(i + 1, x), 100) | |
| } | |
| for(let i = 0; i < 100000; i++) { | |
| s.onNext(i) | |
| } | |
| ss.request(1) |
Why pausable() not work?
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The first subscriber will be blocked until call ss.request(1), therefore it must called into the last callback chain.