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August 13, 2020 20:51
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#include<bits/stdc++.h> | |
using namespace std; | |
#define V 6 //No of vertices | |
int selectMinVertex(vector<int>& value,vector<bool>& processed) | |
{ | |
int minimum = INT_MAX; | |
int vertex; | |
for(int i=0;i<V;++i) | |
{ | |
if(processed[i]==false && value[i]<minimum) | |
{ | |
vertex = i; | |
minimum = value[i]; | |
} | |
} | |
return vertex; | |
} | |
void dijkstra(int graph[V][V]) | |
{ | |
int parent[V]; //Stores Shortest Path Structure | |
vector<int> value(V,INT_MAX); //Keeps shortest path values to each vertex from source | |
vector<bool> processed(V,false); //TRUE->Vertex is processed | |
//Assuming start point as Node-0 | |
parent[0] = -1; //Start node has no parent | |
value[0] = 0; //start node has value=0 to get picked 1st | |
//Include (V-1) edges to cover all V-vertices | |
for(int i=0;i<V-1;++i) | |
{ | |
//Select best Vertex by applying greedy method | |
int U = selectMinVertex(value,processed); | |
processed[U] = true; //Include new Vertex in shortest Path Graph | |
//Relax adjacent vertices (not yet included in shortest path graph) | |
for(int j=0;j<V;++j) | |
{ | |
/* 3 conditions to relax:- | |
1.Edge is present from U to j. | |
2.Vertex j is not included in shortest path graph | |
3.Edge weight is smaller than current edge weight | |
*/ | |
if(graph[U][j]!=0 && processed[j]==false && value[U]!=INT_MAX | |
&& (value[U]+graph[U][j] < value[j])) | |
{ | |
value[j] = value[U]+graph[U][j]; | |
parent[j] = U; | |
} | |
} | |
} | |
//Print Shortest Path Graph | |
for(int i=1;i<V;++i) | |
cout<<"U->V: "<<parent[i]<<"->"<<i<<" wt = "<<graph[parent[i]][i]<<"\n"; | |
} | |
int main() | |
{ | |
int graph[V][V] = { {0, 1, 4, 0, 0, 0}, | |
{1, 0, 4, 2, 7, 0}, | |
{4, 4, 0, 3, 5, 0}, | |
{0, 2, 3, 0, 4, 6}, | |
{0, 7, 5, 4, 0, 7}, | |
{0, 0, 0, 6, 7, 0} }; | |
dijkstra(graph); | |
return 0; | |
} | |
//TIME COMPLEXITY: O(V^2) | |
//TIME COMPLEXITY: (using Min-Heap + Adjacency_List): O(ElogV) |
Colorful code, easy to understand ^_^
#include<bits/stdc++.h>
using namespace std;
#define INF 99999
void addEdge(vector<pair<int, int>> graph[], int u, int v, int w){
graph[u].push_back({v, w});
graph[v].push_back({u, w});
}
void dijkstras(vector<pair<int, int>> graph[], int src, int V){
priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq;
vector<int>dist(V, INF);
pq.push(make_pair(0, src));
dist[src] = 0;
// normal BFS traversal
while(!pq.empty()){
int u = pq.top().second;
pq.pop();
for(auto x : graph[u]){
int v = x.first;
int wt = x.second;
if(dist[v]>dist[u] + wt){
dist[v] = dist[u] + wt;
pq.push(make_pair(dist[v], v));
}
}
}
cout<<"Vertex Distance from src\n";
for(int i=0; i<V; i++)
cout<<i<<"\t"<<dist[i]<<endl;
}
int main(){
int V = 9;
vector<pair<int, int>> graph[V];
addEdge(graph ,0, 1, 4);
addEdge(graph ,0, 7, 8);
addEdge(graph ,1, 2, 8);
addEdge(graph ,1, 7, 11);
addEdge(graph ,2, 3, 7);
addEdge(graph ,2, 8, 2);
addEdge(graph ,2, 5, 4);
addEdge(graph ,3, 4, 9);
addEdge(graph ,3, 5, 14);
addEdge(graph ,4, 5, 10);
addEdge(graph ,5, 6, 2);
addEdge(graph ,6, 7, 1);
addEdge(graph ,6, 8, 6);
addEdge(graph ,7, 8, 7);
dijkstras(graph, 0, 9);
}
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We don't, that's why the priority queue implementation used a lot a memory, for a memory efficient solution, use a set, we cant update a set as well but we can remove at any level and insert a new better distance node, whereas in priority queue random access is not possible.
The Code using set is -
void dijkstraSSSP(int src)
{