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@andrewmilson
Last active October 7, 2024 12:07
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Golang multipart/form-data File Upload
package main
import (
"net/http"
"os"
"bytes"
"path"
"path/filepath"
"mime/multipart"
"io"
)
func main() {
fileDir, _ := os.Getwd()
fileName := "upload-file.txt"
filePath := path.Join(fileDir, fileName)
file, _ := os.Open(filePath)
defer file.Close()
body := &bytes.Buffer{}
writer := multipart.NewWriter(body)
part, _ := writer.CreateFormFile("file", filepath.Base(file.Name()))
io.Copy(part, file)
writer.Close()
r, _ := http.NewRequest("POST", "http://example.com", body)
r.Header.Add("Content-Type", writer.FormDataContentType())
client := &http.Client{}
client.Do(r)
}
@irvanrahadhian
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Thank you

@yedamao
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yedamao commented Aug 6, 2021

👍

@MingyiLiang
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Do you have any ideas how to send a zip file using multipart writer?

@AlfarisiN
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Thanks!! Much appreciated!

@foofybuster
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Thanks! it's working well.

@AnjanaMadu
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Thanks!

@lsdrfrx
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lsdrfrx commented May 12, 2022

Thank you <3

@Jontes-Tech
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Thanks.

@devnote-dev
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Thanks 👍

@pablodz
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pablodz commented May 31, 2022

it works

@zhangpengspin
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it works

@Sujaybiradar25
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Thanks!

@mulder-phenos
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Nice work

@defaultGitCoder
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Thx, nice gist

@episey
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episey commented Sep 29, 2022

Solid

@cadecuddy
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thanks!

@toudi
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toudi commented Oct 18, 2022

if, for whatever reason you need to specify the content type of a part - here's the excerpt:

body := &bytes.Buffer{}
writer := multipart.NewWriter(body)
h := make(textproto.MIMEHeader)
h.Set("Content-Disposition", fmt.Sprintf(`form-data; name="%s"; filename="%s"`, "file", "myfile.xml"))
h.Set("Content-Type", "text/xml")
part, _ := writer.CreatePart(h)

otherwise this code is absolutely perfect, thanks !

@gabrielNetto94
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thanks!

@lnstchtped
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thanks!

@Serares
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Serares commented Jan 14, 2023

Is it possible to compile this in an executable and then whenever you run that '.exe' the server will start to listen on incoming requests?

@pforpramit
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Hello, if I need to upload a zip file as form-data in POST request body, I am able to find this,

zipWriter := zip.NewWriter(buf)
zipFile, err := zipWriter.Create(fileName)

Unlike multipart.Writer, in case of zip.Writer I can't find any option to create form file in a key-value fashion.

How can I achieve this for zip as well?

@PzaThief
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Will this code use sendfile to achieve zero copy?

No It doesn't.
If you want to achieve zero copy, you can use os.pipe instead of sendfile.
sendfile is fit to tcp package so, it is hard to use with http package.
See this code snippet and benchmarks of it.

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